WebException как получить полный ответ с телом?



в WebException я не могу видеть тело GetResponse. Это мой код в C#:



try {                
return GetResponse(url + "." + ext.ToString(), method, headers, bodyParams);
} catch (WebException ex) {
switch (ex.Status) {
case WebExceptionStatus.ConnectFailure:
throw new ConnectionException();
case WebExceptionStatus.Timeout:
throw new RequestTimeRanOutException();
case WebExceptionStatus.NameResolutionFailure:
throw new ConnectionException();
case WebExceptionStatus.ProtocolError:
if (ex.Message == "The remote server returned an error: (401) unauthorized.") {
throw new CredentialsOrPortalException();
}
throw new ProtocolErrorExecption();
default:
throw;
}


Я вижу заголовок, но я не вижу тела. Это вывод из Wireshark для запроса:



POST /api/1.0/authentication.json HTTP/1.1    
Content-Type: application/x-www-form-urlencoded
Accept: application/json
Host: nbm21tm1.teamlab.com
Content-Length: 49
Connection: Keep-Alive

userName=XXX&password=YYYHTTP/1.1 500 Server error
Cache-Control: private, max-age=0
Content-Length: 106
Content-Type: application/json; charset=UTF-8
Server: Microsoft-IIS/7.5
X-AspNet-Version: 2.0.50727
X-Powered-By: ASP.NET
X-Powered-By: ARR/2.5

Date: Mon, 06 Aug 2012 12:49:41 GMT
Connection: close

{"count":0,"startIndex":0,"status":1,"statusCode":500,"error":{"message":"Invalid username or password."}}


можно ли как-то Увидеть текст сообщения в WebException?
Спасибо.

540   3  

3 ответов:

var resp = new StreamReader(ex.Response.GetResponseStream()).ReadToEnd();

dynamic obj = JsonConvert.DeserializeObject(resp);
var messageFromServer = obj.error.message;
try {
 WebClient client = new WebClient();
 client.Encoding = Encoding.UTF8;
 string content = client.DownloadString("https://sandiegodata.atlassian.net/wiki/pages/doaddcomment.action?pageId=524365");
 Console.WriteLine(content);
 Console.ReadKey();
} catch (WebException ex) {
 var resp = new StreamReader(ex.Response.GetResponseStream()).ReadToEnd();
 Console.WriteLine(resp);
 Console.ReadKey();
}

Это только улучшает существующие ответы. Я написал метод, который заботится о деталях броска / переосмысления с улучшенным сообщением, которое включает в себя тело ответа:

вот мой код (в клиенте.cs):

/// <summary>
///     Tries to rethrow the WebException with the data from the body included, if possible. 
///     Otherwise just rethrows the original message.
/// </summary>
/// <param name="wex">The web exception.</param>
/// <exception cref="WebException"></exception>
/// <remarks>
///     By default, on protocol errors, the body is not included in web exceptions. 
///     This solutions includes potentially relevant information for resolving the
///     issue.
/// </remarks>
private void ThrowWithBody(WebException wex) {
    if (wex.Status == WebExceptionStatus.ProtocolError) {
        string responseBody;
        try {
            //Get the message body for rethrow with body included
            responseBody = new StreamReader(wex.Response.GetResponseStream()).ReadToEnd();

        } catch (Exception) {
            //In case of failure to get the body just rethrow the original web exception.
            throw wex;
        }

        //include the body in the message
        throw new WebException(wex.Message + $" Response body: '{responseBody}'", wex, wex.Status, wex.Response);
    }

    //In case of non-protocol errors no body is available anyway, so just rethrow the original web exception.
    throw wex;
}

вы используете его в предложении catch, как показал OP:

//Execute Request, catch the exception to eventually get the body
try {
    //GetResponse....
    }
} catch (WebException wex) {
    if (wex.Status == WebExceptionStatus.ProtocolError) {
        ThrowWithBody(wex);
    }

    //otherwise rethrow anyway
    throw;
}

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